9/x+3-7/x+3=(2/x^2-9)

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Solution for 9/x+3-7/x+3=(2/x^2-9) equation: 



9/x+3-7/x+3=(2/x^2-9)

We move all terms to the left:

9/x+3-7/x+3-((2/x^2-9))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2-9))!=0

x∈R



We add all the numbers together, and all the variables

9/x-7/x-((2/x^2-9))+6=0

We calculate fractions

We do not support expression: x^3

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